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Read csch as the difference of the exponentials with its half gathered elsewhere - #1936
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Rafael-SOWNet merged 3 commits intoOct 18, 2026
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…d elsewhere csch(y) can arrive as (e^y - e^-y)^(-1) beside a 2 the product gathered, and the hyperbolic reader recognised the difference only with its half. It now reads e^y - e^-y as 2 sinh(y) and e^y + e^-y as 2 cosh(y), so csch(c + d x) (a + b sinh(c + d x)^4)^n is answered (Rubi's 6.1.7:237, :247). Co-Authored-By: Claude Opus 5.5 (1M context) <noreply@anthropic.com> Claude-Session: https://claude.ai/code/session_012sonx8iAspMiwRwokT1Ura
…ntegrand-with-a-power-of-a-binomial
…ING-CHANGES Co-Authored-By: Claude Opus 5.5 (1M context) <noreply@anthropic.com> Claude-Session: https://claude.ai/code/session_012sonx8iAspMiwRwokT1Ura
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csch(y)arrives as(e^y - e^-y)^(-1)beside a 2 the product gathered.ReadTheHyperbolicFunctionsrecognised the difference only with its half,(e^y - e^-y)/2. It now readse^y - e^-yas2 sinh(y)ande^y + e^-yas2 cosh(y), only as the base of a whole power.csch(c + d x) (a + b sinh(c + d x)^4)^nran past fifteen minutes on 2.5.0 and is answered in under half a second.Part of #718 — Rubi's 6.1.7:237 and :247.
The whole-power restriction is measured. Read everywhere, the bare difference lost 27 rows of family 6 that master answers (
x/csch(x)^(3/2) + …,sqrt(a + i a csch(c + d x)), …). There the reading handed a root to a rule that then declined it. Restricted, all 27 are answered again.Measured against master b2ef509:
Recorded in BREAKING-CHANGES.md.
🤖 Generated with Claude Code
https://claude.ai/code/session_012sonx8iAspMiwRwokT1Ura